This is the step-by-step, printable version. If you PRINT this page, any ads will not be printed.
See also the animated version.
After doing this | Your work should look like this |
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We start with the triangle ABC. | ![]() |
1. Set the compasses' width to the length of a side of the triangle. Any side will do, but the shortest works best. | ![]() |
2. With the compasses on B, one end of that line, draw an arc across the opposite side. Label this point F | ![]() |
3. Repeat for the other end of the line, C. Label this point P. | ![]() |
*Note If you find you cannot draw these arcs on the opposite sides, the orthocenter is outside the triangle. See note below* | |
What we do now is draw two altitudes. This is the same process as constructing a perpendicular to a line through a point. | |
4. With the compasses on B, set the compasses' width to more than half the distance to P. | ![]() |
5. From B and P, draw two arcs that intersect, creating point Q. | ![]() |
6. Use a straightedge to draw a line from C to Q. The part of this line inside the triangle forms an altitude of the triangle. | ![]() |
Now we repeat the process to create a second altitude. | |
7. With the compasses on C, set the compasses' width tomore than half the distance to F. | ![]() |
8. From C and F, draw two arcs that intersect, creating point E. | ![]() |
9. Use a straightedge to draw a line from B to E. The part of this line inside the triangle forms an altitude of the triangle. | ![]() |
10. Done. The point where the two altitudes intersect is the orthocenter of the triangle. (You may need to extend the altitude lines so they intersect if the orthocenter is outside the triangle) | ![]() |
Optional Step 11.
Repeat steps 7,8,9 on the third side of the triangle. This will help convince you that all three altitudes do in fact intersect at a single point. But two altitudes are enough to find that point. |